full transcript
"From the Ted Talk by Tanya Khovanova: Can you solve the Leonardo da Vinci riddle?"

#### Unscramble the Blue Letters

Why go through all that? Well, we now know something important: the total qiautnty of non-zero digits that occur after the first digit is equal to the sum of these digits, minus one. And how can you get a distribution where the sum is exactly 1 gretaer than the number of non-zero positive integers being added together? The only way is for one of the addends to be a 2, and the rest 1s. How many 1s? Turns out there can only be two – any more would require atnaddoiil digits like 3 or 4 to count them.

#### Open Cloze

Why go through all that? Well, we now know something important: the total **________** of non-zero digits that occur after the first digit is equal to the sum of these digits, minus one. And how can you get a distribution where the sum is exactly 1 **_______** than the number of non-zero positive integers being added together? The only way is for one of the addends to be a 2, and the rest 1s. How many 1s? Turns out there can only be two – any more would require **__________** digits like 3 or 4 to count them.

#### Solution

- additional
- quantity
- greater

#### Original Text

Why go through all that? Well, we now know something important: the total quantity of non-zero digits that occur after the first digit is equal to the sum of these digits, minus one. And how can you get a distribution where the sum is exactly 1 greater than the number of non-zero positive integers being added together? The only way is for one of the addends to be a 2, and the rest 1s. How many 1s? Turns out there can only be two – any more would require additional digits like 3 or 4 to count them.
#### ngrams of length 2

collocation |
frequency |

leading digit |
5 |

#### Important Words

- added
- addends
- additional
- count
- digit
- digits
- distribution
- equal
- greater
- integers
- number
- occur
- positive
- quantity
- require
- rest
- sum
- total
- turns